# Maths Exemplar Solutions Ncert Class Ix

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class ix chapter 4 structure of atom ncert solutions page 47 q1

Its electronic conigiration = 2, 8, 6 Valency of S = 8 – 6 = 2 Magnesium: At. no. of Mg = 12 Its electronic configuration = 2, 8, 2 Valency of Mg = 2 Concept insight: As we know, when the outermost shell of an atom contains 4 or less than 4 electrons, its valency is equal to the number of valence electrons in the outermost shell. Page 52 Q1. If number of electrons in an atom is 8 and number of protons is also 8, then (i) what is the atomic number of the atom? and (ii) what is the charge on the atom? Ans. .ncert class mathematics (size: 5.1m) examrace

2.2. In fact, for any quadratic polynomial ax2 + bx + c, a 0, the graph of the corresponding equation y = ax2 + bx + c has one of the two shapes either open or open upwards like downwards like depending on whether a > 0 or a <(These curves are called parabolas.) You can see from Table 2.1 that –1 and 4 are zeroes of the quadratic polynomial. Also note from Fig. 2.2 that –1 and 4 are the x-coordinates of the points where the graph of y = x2 – 3x – 4 intersects the x- axis. Thus, the zeroes of the .ncert class mathematics problems (size: 2.5m examrace

. system of education. The textbooks for Classes IX and XI were released in 2006 and for Classes X and XII in 2007. Overall.ncert class mathematics (size: 5.9m) examrace

1. Use the given digits without repetition and make the greatest and smallest 4-digit numbers. (a) 2, 8, 7, 4 (b) 9, 7, 4, 1 (c) 4, 7, 5, 0 (d) 1, 7, 6, 2 (e) 5, 4, 0, 3 (Hint : 0754 is a 3-digit number.)Now make the greatest and the smallest 4-digit numbers by using any one digit twice. (a) 3, 8, 7 (b) 9, 0, 5 (c) 0, 4, 9 (d) 8, 5, 1 (Hint : Think in each case which digit will you use twice.)Make the greatest and the smallest 4-digit numbers using any four different digits with conditions as given. (a) .ncert class mathematics (size: 4.5m) examrace

Subtraction is opposite of addition and therefore, we add the additive inverse of the integer that is being subtracted, to the other integer. For example: (a) 56 – 73 = 56 + additive inverse of 73 = 56 + (–73) = –17 (b) 56 – (–73) = 56 + additive inverse of (–73) = 56 + 73 = 129 (c) (–79) – 45 = (–79) + (– 45) = –124 (d) (–100) – (–172) = –100 + 172 = 72 etc. Write atleast five such examples to verify this statement. Thus, we find that for any two integers a and b, a – b = a + additive inverse of b = a + .
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